-2(2k+2)-4(3-k)=3(3k+2)-7

Solution for -2(2k+2)-4(3-k)=3(3k+2)-7 equation:

-2(2k+2)-4(3-k)=3(3k+2)-7

We move all terms to the left:

-2(2k+2)-4(3-k)-(3(3k+2)-7)=0

We add all the numbers together, and all the variables

-2(2k+2)-4(-1k+3)-(3(3k+2)-7)=0

We multiply parentheses

-4k+4k-(3(3k+2)-7)-4-12=0


We calculate terms in parentheses: -(3(3k+2)-7), so:

3(3k+2)-7

We multiply parentheses

9k+6-7

We add all the numbers together, and all the variables

9k-1

Back to the equation:

-(9k-1)


We add all the numbers together, and all the variables

-(9k-1)-16=0

We get rid of parentheses

-9k+1-16=0

We add all the numbers together, and all the variables

-9k-15=0

We move all terms containing k to the left, all other terms to the right

-9k=15

k=15/-9

k=-1+2/3