-2(2+5r)+(6r-3)=6r+7r

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Solution for -2(2+5r)+(6r-3)=6r+7r equation: 



-2(2+5r)+(6r-3)=6r+7r

We move all terms to the left:

-2(2+5r)+(6r-3)-(6r+7r)=0

We add all the numbers together, and all the variables

-2(5r+2)+(6r-3)-(+13r)=0

We multiply parentheses

-10r+(6r-3)-(+13r)-4=0

We get rid of parentheses

-10r+6r-13r-3-4=0

We add all the numbers together, and all the variables

-17r-7=0

We move all terms containing r to the left, all other terms to the right

-17r=7

r=7/-17

r=-7/17

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