-2(13z-10)=20+3z

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Solution for -2(13z-10)=20+3z equation: 



-2(13z-10)=20+3z

We move all terms to the left:

-2(13z-10)-(20+3z)=0

We add all the numbers together, and all the variables

-2(13z-10)-(3z+20)=0

We multiply parentheses

-26z-(3z+20)+20=0

We get rid of parentheses

-26z-3z-20+20=0

We add all the numbers together, and all the variables

-29z=0

z=0/-29

z=0

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