-2(10z-2)=-3(-2+6z)

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Solution for -2(10z-2)=-3(-2+6z) equation: 



-2(10z-2)=-3(-2+6z)

We move all terms to the left:

-2(10z-2)-(-3(-2+6z))=0

We add all the numbers together, and all the variables

-2(10z-2)-(-3(6z-2))=0

We multiply parentheses

-20z-(-3(6z-2))+4=0



We calculate terms in parentheses: -(-3(6z-2)), so:

-3(6z-2)

We multiply parentheses

-18z+6

Back to the equation:

-(-18z+6)



We get rid of parentheses

-20z+18z-6+4=0

We add all the numbers together, and all the variables

-2z-2=0

We move all terms containing z to the left, all other terms to the right

-2z=2

z=2/-2

z=-1

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