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-2(1-3v)=-(2-v)
We move all terms to the left:
-2(1-3v)-(-(2-v))=0
We add all the numbers together, and all the variables
-2(-3v+1)-(-(-1v+2))=0
We multiply parentheses
6v-(-(-1v+2))-2=0
We calculate terms in parentheses: -(-(-1v+2)), so:We get rid of parentheses
-(-1v+2)
We get rid of parentheses
1v-2
We add all the numbers together, and all the variables
v-2
Back to the equation:
-(v-2)
6v-v+2-2=0
We add all the numbers together, and all the variables
5v=0
v=0/5
v=0
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