-2(1-2a)=4(5/4a-3)

Solution for -2(1-2a)=4(5/4a-3) equation:

-2(1-2a)=4(5/4a-3)

We move all terms to the left:

-2(1-2a)-(4(5/4a-3))=0


Domain of the equation: 4a-3))!=0

a∈R


We add all the numbers together, and all the variables

-2(-2a+1)-(4(5/4a-3))=0

We multiply parentheses

4a-(4(5/4a-3))-2=0

We multiply all the terms by the denominator


4a*4a-2*4a-3))-(4(5-3))=0

We add all the numbers together, and all the variables

4a*4a-2*4a-3))-(42)=0

We add all the numbers together, and all the variables

4a*4a-2*4a=0

Wy multiply elements

16a^2-8a=0

a = 16; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·16·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*16}=\frac{0}{32}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*16}=\frac{16}{32}
=1/2
$