-2(1+v)=2+2(v+8)

Solution for -2(1+v)=2+2(v+8) equation:

-2(1+v)=2+2(v+8)

We move all terms to the left:

-2(1+v)-(2+2(v+8))=0

We add all the numbers together, and all the variables

-2(v+1)-(2+2(v+8))=0

We multiply parentheses

-2v-(2+2(v+8))-2=0


We calculate terms in parentheses: -(2+2(v+8)), so:

2+2(v+8)

determiningTheFunctionDomain
2(v+8)+2

We multiply parentheses

2v+16+2

We add all the numbers together, and all the variables

2v+18

Back to the equation:

-(2v+18)


We get rid of parentheses

-2v-2v-18-2=0

We add all the numbers together, and all the variables

-4v-20=0

We move all terms containing v to the left, all other terms to the right

-4v=20

v=20/-4

v=-5