-2(1+2v)=2(5v-1)

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Solution for -2(1+2v)=2(5v-1) equation: 



-2(1+2v)=2(5v-1)

We move all terms to the left:

-2(1+2v)-(2(5v-1))=0

We add all the numbers together, and all the variables

-2(2v+1)-(2(5v-1))=0

We multiply parentheses

-4v-(2(5v-1))-2=0



We calculate terms in parentheses: -(2(5v-1)), so:

2(5v-1)

We multiply parentheses

10v-2

Back to the equation:

-(10v-2)



We get rid of parentheses

-4v-10v+2-2=0

We add all the numbers together, and all the variables

-14v=0

v=0/-14

v=0

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