-2(-x-4)+3=7(2x-1)+6

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Solution for -2(-x-4)+3=7(2x-1)+6 equation: 



-2(-x-4)+3=7(2x-1)+6

We move all terms to the left:

-2(-x-4)+3-(7(2x-1)+6)=0

We add all the numbers together, and all the variables

-2(-1x-4)-(7(2x-1)+6)+3=0

We multiply parentheses

2x-(7(2x-1)+6)+8+3=0



We calculate terms in parentheses: -(7(2x-1)+6), so:

7(2x-1)+6

We multiply parentheses

14x-7+6

We add all the numbers together, and all the variables

14x-1

Back to the equation:

-(14x-1)



We add all the numbers together, and all the variables

2x-(14x-1)+11=0

We get rid of parentheses

2x-14x+1+11=0

We add all the numbers together, and all the variables

-12x+12=0

We move all terms containing x to the left, all other terms to the right

-12x=-12

x=-12/-12

x=1

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