-2(-x+4)3x+2=-5

Solution for -2(-x+4)3x+2=-5 equation:

-2(-x+4)3x+2=-5

We move all terms to the left:

-2(-x+4)3x+2-(-5)=0

We add all the numbers together, and all the variables

-2(-1x+4)3x+2-(-5)=0

We add all the numbers together, and all the variables

-2(-1x+4)3x+7=0

We multiply parentheses

6x^2-24x+7=0

a = 6; b = -24; c = +7;
Δ = b2-4ac
Δ = -242-4·6·7
Δ = 408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{408}=\sqrt{4*102}=\sqrt{4}*\sqrt{102}=2\sqrt{102}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-2\sqrt{102}}{2*6}=\frac{24-2\sqrt{102}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+2\sqrt{102}}{2*6}=\frac{24+2\sqrt{102}}{12}
$