-2(-8y+4)-4y=2(y-5)-6

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Solution for -2(-8y+4)-4y=2(y-5)-6 equation: 



-2(-8y+4)-4y=2(y-5)-6

We move all terms to the left:

-2(-8y+4)-4y-(2(y-5)-6)=0

We add all the numbers together, and all the variables

-4y-2(-8y+4)-(2(y-5)-6)=0

We multiply parentheses

-4y+16y-(2(y-5)-6)-8=0



We calculate terms in parentheses: -(2(y-5)-6), so:

2(y-5)-6

We multiply parentheses

2y-10-6

We add all the numbers together, and all the variables

2y-16

Back to the equation:

-(2y-16)



We add all the numbers together, and all the variables

12y-(2y-16)-8=0

We get rid of parentheses

12y-2y+16-8=0

We add all the numbers together, and all the variables

10y+8=0

We move all terms containing y to the left, all other terms to the right

10y=-8

y=-8/10

y=-4/5

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