-2(-3x+3)*2x=58

Solution for -2(-3x+3)*2x=58 equation:

-2(-3x+3)*2x=58

We move all terms to the left:

-2(-3x+3)*2x-(58)=0

We multiply parentheses

12x^2-12x-58=0

a = 12; b = -12; c = -58;
Δ = b2-4ac
Δ = -122-4·12·(-58)
Δ = 2928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2928}=\sqrt{16*183}=\sqrt{16}*\sqrt{183}=4\sqrt{183}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{183}}{2*12}=\frac{12-4\sqrt{183}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{183}}{2*12}=\frac{12+4\sqrt{183}}{24}
$