-2(-10v-12)=6-9(v-2)

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Solution for -2(-10v-12)=6-9(v-2) equation: 



-2(-10v-12)=6-9(v-2)

We move all terms to the left:

-2(-10v-12)-(6-9(v-2))=0

We multiply parentheses

20v-(6-9(v-2))+24=0



We calculate terms in parentheses: -(6-9(v-2)), so:

6-9(v-2)

determiningTheFunctionDomain
-9(v-2)+6

We multiply parentheses

-9v+18+6

We add all the numbers together, and all the variables

-9v+24

Back to the equation:

-(-9v+24)



We get rid of parentheses

20v+9v-24+24=0

We add all the numbers together, and all the variables

29v=0

v=0/29

v=0

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