-2((-k-3)(-2)-3)=(-3-3k)(-8)-9

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Solution for -2((-k-3)(-2)-3)=(-3-3k)(-8)-9 equation: 



-2((-k-3)(-2)-3)=(-3-3k)(-8)-9

We move all terms to the left:

-2((-k-3)(-2)-3)-((-3-3k)(-8)-9)=0

We add all the numbers together, and all the variables

-2((-1k-3)(-2)-3)-((-3k-3)(-8)-9)=0

We multiply parentheses ..

-2((+2k+6)-3)-((-3k-3)(-8)-9)=0



We calculate terms in parentheses: -((-3k-3)(-8)-9), so:

(-3k-3)(-8)-9

We multiply parentheses ..

(+24k+24)-9

We add all the numbers together, and all the variables

(24k+24)-9

We get rid of parentheses

24k+24-9

We add all the numbers together, and all the variables

24k+15

Back to the equation:

-(24k+15)



We add all the numbers together, and all the variables

-2((2k+6)-3)-(24k+15)=0

We get rid of parentheses

-2((2k+6)-3)-24k-15=0

We add all the numbers together, and all the variables

-24k-2((2k+6)-3)-15=0

We move all terms containing k to the left, all other terms to the right

-24k-2((2k+6)-3)=15

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