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-1x+60=8/5x+72
We move all terms to the left:
-1x+60-(8/5x+72)=0
Domain of the equation: 5x+72)!=0We get rid of parentheses
x∈R
-1x-8/5x-72+60=0
We multiply all the terms by the denominator
-1x*5x-72*5x+60*5x-8=0
Wy multiply elements
-5x^2-360x+300x-8=0
We add all the numbers together, and all the variables
-5x^2-60x-8=0
a = -5; b = -60; c = -8;
Δ = b2-4ac
Δ = -602-4·(-5)·(-8)
Δ = 3440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3440}=\sqrt{16*215}=\sqrt{16}*\sqrt{215}=4\sqrt{215}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-4\sqrt{215}}{2*-5}=\frac{60-4\sqrt{215}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+4\sqrt{215}}{2*-5}=\frac{60+4\sqrt{215}}{-10} $
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