-1=3(j+5)+-1

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Solution for -1=3(j+5)+-1 equation: 



-1=3(j+5)+-1

We move all terms to the left:

-1-(3(j+5)+-1)=0

We use the square of the difference formula

-(3(j+5)-1)-1=0



We calculate terms in parentheses: -(3(j+5)-1), so:

3(j+5)-1

We multiply parentheses

3j+15-1

We add all the numbers together, and all the variables

3j+14

Back to the equation:

-(3j+14)



We get rid of parentheses

-3j-14-1=0

We add all the numbers together, and all the variables

-3j-15=0

We move all terms containing j to the left, all other terms to the right

-3j=15

j=15/-3

j=-5

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