-1=-8y+3(y-2)

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Solution for -1=-8y+3(y-2) equation: 



-1=-8y+3(y-2)

We move all terms to the left:

-1-(-8y+3(y-2))=0



We calculate terms in parentheses: -(-8y+3(y-2)), so:

-8y+3(y-2)

We multiply parentheses

-8y+3y-6

We add all the numbers together, and all the variables

-5y-6

Back to the equation:

-(-5y-6)



We get rid of parentheses

5y+6-1=0

We add all the numbers together, and all the variables

5y+5=0

We move all terms containing y to the left, all other terms to the right

5y=-5

y=-5/5

y=-1

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