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-18x^2+6400x+-180.400=0
We add all the numbers together, and all the variables
-18x^2+6400x=0
a = -18; b = 6400; c = 0;
Δ = b2-4ac
Δ = 64002-4·(-18)·0
Δ = 40960000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40960000}=6400$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6400)-6400}{2*-18}=\frac{-12800}{-36} =355+5/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6400)+6400}{2*-18}=\frac{0}{-36} =0 $
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