-18j(-9j)+(-11)+j-(-6j)+(-6)=20

Solution for -18j(-9j)+(-11)+j-(-6j)+(-6)=20 equation:

-18j(-9j)+(-11)+j-(-6j)+(-6)=20

We move all terms to the left:

-18j(-9j)+(-11)+j-(-6j)+(-6)-(20)=0

determiningTheFunctionDomain
-18j(-9j)+j-(-6j)-20+(-11)+(-6)=0

We add all the numbers together, and all the variables

j-18j(-9j)-(-6j)-37=0

We multiply parentheses

162j^2+j-(-6j)-37=0

We get rid of parentheses

162j^2+j+6j-37=0

We add all the numbers together, and all the variables

162j^2+7j-37=0

a = 162; b = 7; c = -37;
Δ = b2-4ac
Δ = 72-4·162·(-37)
Δ = 24025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24025}=155$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-155}{2*162}=\frac{-162}{324}
=-1/2
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+155}{2*162}=\frac{148}{324}
=37/81
$