-16x2+4.8x=0

Solution for -16x2+4.8x=0 equation:

-16x^2+4.8x=0

a = -16; b = 4.8; c = 0;
Δ = b2-4ac
Δ = 4.82-4·(-16)·0
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.8)-\sqrt{23.04}}{2*-16}=\frac{-4.8-\sqrt{23.04}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.8)+\sqrt{23.04}}{2*-16}=\frac{-4.8+\sqrt{23.04}}{-32}
$