-16x2+26x+0=0

Solution for -16x2+26x+0=0 equation:

-16x^2+26x+0=0

We add all the numbers together, and all the variables

-16x^2+26x=0

a = -16; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·(-16)·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*-16}=\frac{-52}{-32}
=1+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*-16}=\frac{0}{-32}
=0
$