-16=2(v+2)-6v

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Solution for -16=2(v+2)-6v equation: 



-16=2(v+2)-6v

We move all terms to the left:

-16-(2(v+2)-6v)=0



We calculate terms in parentheses: -(2(v+2)-6v), so:

2(v+2)-6v

We add all the numbers together, and all the variables

-6v+2(v+2)

We multiply parentheses

-6v+2v+4

We add all the numbers together, and all the variables

-4v+4

Back to the equation:

-(-4v+4)



We get rid of parentheses

4v-4-16=0

We add all the numbers together, and all the variables

4v-20=0

We move all terms containing v to the left, all other terms to the right

4v=20

v=20/4

v=5

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