-16-6x=-6x(x+3)

Solution for -16-6x=-6x(x+3) equation:

-16-6x=-6x(x+3)

We move all terms to the left:

-16-6x-(-6x(x+3))=0


We calculate terms in parentheses: -(-6x(x+3)), so:

-6x(x+3)

We multiply parentheses

-6x^2-18x

Back to the equation:

-(-6x^2-18x)


We get rid of parentheses

6x^2+18x-6x-16=0

We add all the numbers together, and all the variables

6x^2+12x-16=0

a = 6; b = 12; c = -16;
Δ = b2-4ac
Δ = 122-4·6·(-16)
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{33}}{2*6}=\frac{-12-4\sqrt{33}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{33}}{2*6}=\frac{-12+4\sqrt{33}}{12}
$