-16(x-2)+32x=16(x+4)-32

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Solution for -16(x-2)+32x=16(x+4)-32 equation:


Simplifying
-16(x + -2) + 32x = 16(x + 4) + -32

Reorder the terms:
-16(-2 + x) + 32x = 16(x + 4) + -32
(-2 * -16 + x * -16) + 32x = 16(x + 4) + -32
(32 + -16x) + 32x = 16(x + 4) + -32

Combine like terms: -16x + 32x = 16x
32 + 16x = 16(x + 4) + -32

Reorder the terms:
32 + 16x = 16(4 + x) + -32
32 + 16x = (4 * 16 + x * 16) + -32
32 + 16x = (64 + 16x) + -32

Reorder the terms:
32 + 16x = 64 + -32 + 16x

Combine like terms: 64 + -32 = 32
32 + 16x = 32 + 16x

Add '-32' to each side of the equation.
32 + -32 + 16x = 32 + -32 + 16x

Combine like terms: 32 + -32 = 0
0 + 16x = 32 + -32 + 16x
16x = 32 + -32 + 16x

Combine like terms: 32 + -32 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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