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-15x^2+96x-36=0
a = -15; b = 96; c = -36;
Δ = b2-4ac
Δ = 962-4·(-15)·(-36)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-84}{2*-15}=\frac{-180}{-30} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+84}{2*-15}=\frac{-12}{-30} =2/5 $
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