-15+5(1+3z)=z-5(4-2z)

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Solution for -15+5(1+3z)=z-5(4-2z) equation: 



-15+5(1+3z)=z-5(4-2z)

We move all terms to the left:

-15+5(1+3z)-(z-5(4-2z))=0

We add all the numbers together, and all the variables

5(3z+1)-(z-5(-2z+4))-15=0

We multiply parentheses

15z-(z-5(-2z+4))+5-15=0



We calculate terms in parentheses: -(z-5(-2z+4)), so:

z-5(-2z+4)

We multiply parentheses

z+10z-20

We add all the numbers together, and all the variables

11z-20

Back to the equation:

-(11z-20)



We add all the numbers together, and all the variables

15z-(11z-20)-10=0

We get rid of parentheses

15z-11z+20-10=0

We add all the numbers together, and all the variables

4z+10=0

We move all terms containing z to the left, all other terms to the right

4z=-10

z=-10/4

z=-2+1/2

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