-15(z+2)+5(4z-5)=4(z-3)+11

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Solution for -15(z+2)+5(4z-5)=4(z-3)+11 equation: 



-15(z+2)+5(4z-5)=4(z-3)+11

We move all terms to the left:

-15(z+2)+5(4z-5)-(4(z-3)+11)=0

We multiply parentheses

-15z+20z-(4(z-3)+11)-30-25=0



We calculate terms in parentheses: -(4(z-3)+11), so:

4(z-3)+11

We multiply parentheses

4z-12+11

We add all the numbers together, and all the variables

4z-1

Back to the equation:

-(4z-1)



We add all the numbers together, and all the variables

5z-(4z-1)-55=0

We get rid of parentheses

5z-4z+1-55=0

We add all the numbers together, and all the variables

z-54=0

We move all terms containing z to the left, all other terms to the right

z=54

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