-14=3(1+d)-20

Solution for -14=3(1+d)-20 equation:

-14=3(1+d)-20

We move all terms to the left:

-14-(3(1+d)-20)=0

We add all the numbers together, and all the variables

-(3(d+1)-20)-14=0


We calculate terms in parentheses: -(3(d+1)-20), so:

3(d+1)-20

We multiply parentheses

3d+3-20

We add all the numbers together, and all the variables

3d-17

Back to the equation:

-(3d-17)


We get rid of parentheses

-3d+17-14=0

We add all the numbers together, and all the variables

-3d+3=0

We move all terms containing d to the left, all other terms to the right

-3d=-3

d=-3/-3

d=1