-14+8(t+2)=6-9(1t+4)

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Solution for -14+8(t+2)=6-9(1t+4) equation: 



-14+8(t+2)=6-9(1t+4)

We move all terms to the left:

-14+8(t+2)-(6-9(1t+4))=0

We add all the numbers together, and all the variables

8(t+2)-(6-9(t+4))-14=0

We multiply parentheses

8t-(6-9(t+4))+16-14=0



We calculate terms in parentheses: -(6-9(t+4)), so:

6-9(t+4)

determiningTheFunctionDomain
-9(t+4)+6

We multiply parentheses

-9t-36+6

We add all the numbers together, and all the variables

-9t-30

Back to the equation:

-(-9t-30)



We add all the numbers together, and all the variables

8t-(-9t-30)+2=0

We get rid of parentheses

8t+9t+30+2=0

We add all the numbers together, and all the variables

17t+32=0

We move all terms containing t to the left, all other terms to the right

17t=-32

t=-32/17

t=-1+15/17

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