-13=2(y-3)+5y

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Solution for -13=2(y-3)+5y equation: 



-13=2(y-3)+5y

We move all terms to the left:

-13-(2(y-3)+5y)=0



We calculate terms in parentheses: -(2(y-3)+5y), so:

2(y-3)+5y

We add all the numbers together, and all the variables

5y+2(y-3)

We multiply parentheses

5y+2y-6

We add all the numbers together, and all the variables

7y-6

Back to the equation:

-(7y-6)



We get rid of parentheses

-7y+6-13=0

We add all the numbers together, and all the variables

-7y-7=0

We move all terms containing y to the left, all other terms to the right

-7y=7

y=7/-7

y=-1

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