-13/10x+1/2x=-56

Solution for -13/10x+1/2x=-56 equation:

-13/10x+1/2x=-56

We move all terms to the left:

-13/10x+1/2x-(-56)=0


Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

-13/10x+1/2x+56=0

We calculate fractions


(-26x)/20x^2+10x/20x^2+56=0

We multiply all the terms by the denominator


(-26x)+10x+56*20x^2=0

We add all the numbers together, and all the variables

10x+(-26x)+56*20x^2=0

Wy multiply elements

1120x^2+10x+(-26x)=0

We get rid of parentheses

1120x^2+10x-26x=0

We add all the numbers together, and all the variables

1120x^2-16x=0

a = 1120; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·1120·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*1120}=\frac{0}{2240}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*1120}=\frac{32}{2240}
=1/70
$