-12x+26=-(1/5)-x+2+3

Solution for -12x+26=-(1/5)-x+2+3 equation:

-12x+26=-(1/5)-x+2+3

We move all terms to the left:

-12x+26-(-(1/5)-x+2+3)=0


Domain of the equation: 5)-x+2+3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-12x-(-(+1/5)-x+2+3)+26=0

We multiply all the terms by the denominator


-12x*5)-x+2+3)-(-(+26*5)-x+2+3)+1=0

We add all the numbers together, and all the variables

-12x*5)-x+2+3)-(-130-x+2+3)+1=0

Wy multiply elements

-60x^2=0

a = -60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-60)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-120}=0$