-12x+(3*4-(3+x))=1/x

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Solution for -12x+(3*4-(3+x))=1/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*4-12*x-x-3 = 1/x // - 1/x

3*4-12*x-x-(1/x)-3 = 0

3*4-12*x-x-x^-1-3 = 0

9*x^0-13*x^1-1*x^-1 = 0

(9*x^1-13*x^2-1*x^0)/(x^1) = 0 // * x^2

x^1*(9*x^1-13*x^2-1*x^0) = 0

x^1

9*x-13*x^2-1 = 0

9*x-13*x^2-1 = 0

DELTA = 9^2-(-13*(-1)*4)

DELTA = 29

DELTA > 0

x = (29^(1/2)-9)/(-13*2) or x = (-29^(1/2)-9)/(-13*2)

x = (29^(1/2)-9)/(-26) or x = (29^(1/2)+9)/26

x in { (29^(1/2)-9)/(-26), (29^(1/2)+9)/26}

x in { (29^(1/2)-9)/(-26), (29^(1/2)+9)/26 }

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