-12j+4+2j(6j+1)=6

Solution for -12j+4+2j(6j+1)=6 equation:

-12j+4+2j(6j+1)=6

We move all terms to the left:

-12j+4+2j(6j+1)-(6)=0

We add all the numbers together, and all the variables

-12j+2j(6j+1)-2=0

We multiply parentheses

12j^2-12j+2j-2=0

We add all the numbers together, and all the variables

12j^2-10j-2=0

a = 12; b = -10; c = -2;
Δ = b2-4ac
Δ = -102-4·12·(-2)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*12}=\frac{-4}{24}
=-1/6
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*12}=\frac{24}{24}
=1
$