-12=3(t-2)-t

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Solution for -12=3(t-2)-t equation: 



-12=3(t-2)-t

We move all terms to the left:

-12-(3(t-2)-t)=0



We calculate terms in parentheses: -(3(t-2)-t), so:

3(t-2)-t

We add all the numbers together, and all the variables

-1t+3(t-2)

We multiply parentheses

-1t+3t-6

We add all the numbers together, and all the variables

2t-6

Back to the equation:

-(2t-6)



We get rid of parentheses

-2t+6-12=0

We add all the numbers together, and all the variables

-2t-6=0

We move all terms containing t to the left, all other terms to the right

-2t=6

t=6/-2

t=-3

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