-129=-3(4z+7)

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Solution for -129=-3(4z+7) equation: 



-129=-3(4z+7)

We move all terms to the left:

-129-(-3(4z+7))=0



We calculate terms in parentheses: -(-3(4z+7)), so:

-3(4z+7)

We multiply parentheses

-12z-21

Back to the equation:

-(-12z-21)



We get rid of parentheses

12z+21-129=0

We add all the numbers together, and all the variables

12z-108=0

We move all terms containing z to the left, all other terms to the right

12z=108

z=108/12

z=9

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