-128=6b+5(1-5b)

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Solution for -128=6b+5(1-5b) equation:



-128=6b+5(1-5b)
We move all terms to the left:
-128-(6b+5(1-5b))=0
We add all the numbers together, and all the variables
-(6b+5(-5b+1))-128=0
We calculate terms in parentheses: -(6b+5(-5b+1)), so:
6b+5(-5b+1)
We multiply parentheses
6b-25b+5
We add all the numbers together, and all the variables
-19b+5
Back to the equation:
-(-19b+5)
We get rid of parentheses
19b-5-128=0
We add all the numbers together, and all the variables
19b-133=0
We move all terms containing b to the left, all other terms to the right
19b=133
b=133/19
b=7

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