-128=4(3+7k)

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Solution for -128=4(3+7k) equation: 



-128=4(3+7k)

We move all terms to the left:

-128-(4(3+7k))=0

We add all the numbers together, and all the variables

-(4(7k+3))-128=0



We calculate terms in parentheses: -(4(7k+3)), so:

4(7k+3)

We multiply parentheses

28k+12

Back to the equation:

-(28k+12)



We get rid of parentheses

-28k-12-128=0

We add all the numbers together, and all the variables

-28k-140=0

We move all terms containing k to the left, all other terms to the right

-28k=140

k=140/-28

k=-5

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