-12-4(3x-(6+2x))=4(x-5)

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Solution for -12-4(3x-(6+2x))=4(x-5) equation: 



-12-4(3x-(6+2x))=4(x-5)

We move all terms to the left:

-12-4(3x-(6+2x))-(4(x-5))=0

We add all the numbers together, and all the variables

-4(3x-(2x+6))-(4(x-5))-12=0



We calculate terms in parentheses: -(4(x-5)), so:

4(x-5)

We multiply parentheses

4x-20

Back to the equation:

-(4x-20)



We get rid of parentheses

-4(3x-(2x+6))-4x+20-12=0

We add all the numbers together, and all the variables

-4x-4(3x-(2x+6))+8=0

We move all terms containing x to the left, all other terms to the right

-4x-4(3x-(2x+6))=-8

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