-12+3k=-3k+6(k-2)

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Solution for -12+3k=-3k+6(k-2) equation: 



-12+3k=-3k+6(k-2)

We move all terms to the left:

-12+3k-(-3k+6(k-2))=0



We calculate terms in parentheses: -(-3k+6(k-2)), so:

-3k+6(k-2)

We multiply parentheses

-3k+6k-12

We add all the numbers together, and all the variables

3k-12

Back to the equation:

-(3k-12)



We get rid of parentheses

3k-3k+12-12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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