-12+(x-5)=-4+3(5x-2)

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Solution for -12+(x-5)=-4+3(5x-2) equation: 



-12+(x-5)=-4+3(5x-2)

We move all terms to the left:

-12+(x-5)-(-4+3(5x-2))=0

We get rid of parentheses

x-(-4+3(5x-2))-5-12=0



We calculate terms in parentheses: -(-4+3(5x-2)), so:

-4+3(5x-2)

determiningTheFunctionDomain
3(5x-2)-4

We multiply parentheses

15x-6-4

We add all the numbers together, and all the variables

15x-10

Back to the equation:

-(15x-10)



We add all the numbers together, and all the variables

x-(15x-10)-17=0

We get rid of parentheses

x-15x+10-17=0

We add all the numbers together, and all the variables

-14x-7=0

We move all terms containing x to the left, all other terms to the right

-14x=7

x=7/-14

x=-1/2

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