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-12(v-11)=2v-4(1-5v)
We move all terms to the left:
-12(v-11)-(2v-4(1-5v))=0
We add all the numbers together, and all the variables
-12(v-11)-(2v-4(-5v+1))=0
We multiply parentheses
-12v-(2v-4(-5v+1))+132=0
We calculate terms in parentheses: -(2v-4(-5v+1)), so:We get rid of parentheses
2v-4(-5v+1)
We multiply parentheses
2v+20v-4
We add all the numbers together, and all the variables
22v-4
Back to the equation:
-(22v-4)
-12v-22v+4+132=0
We add all the numbers together, and all the variables
-34v+136=0
We move all terms containing v to the left, all other terms to the right
-34v=-136
v=-136/-34
v=+4
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