-118=n-3(1+8n)

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Solution for -118=n-3(1+8n) equation: 



-118=n-3(1+8n)

We move all terms to the left:

-118-(n-3(1+8n))=0

We add all the numbers together, and all the variables

-(n-3(8n+1))-118=0



We calculate terms in parentheses: -(n-3(8n+1)), so:

n-3(8n+1)

We multiply parentheses

n-24n-3

We add all the numbers together, and all the variables

-23n-3

Back to the equation:

-(-23n-3)



We get rid of parentheses

23n+3-118=0

We add all the numbers together, and all the variables

23n-115=0

We move all terms containing n to the left, all other terms to the right

23n=115

n=115/23

n=5

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