-11/6b-3/2b=-14/3

Solution for -11/6b-3/2b=-14/3 equation:

-11/6b-3/2b=-14/3

We move all terms to the left:

-11/6b-3/2b-(-14/3)=0


Domain of the equation: 6b!=0

b!=0/6

b!=0

b∈R



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We get rid of parentheses

-11/6b-3/2b+14/3=0

We calculate fractions


336b^2/108b^2+(-198b)/108b^2+(-162b)/108b^2=0

We multiply all the terms by the denominator


336b^2+(-198b)+(-162b)=0

We get rid of parentheses

336b^2-198b-162b=0

We add all the numbers together, and all the variables

336b^2-360b=0

a = 336; b = -360; c = 0;
Δ = b2-4ac
Δ = -3602-4·336·0
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-360}{2*336}=\frac{0}{672}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+360}{2*336}=\frac{720}{672}
=1+1/14
$