-11-7+3(2n-5)=-2(4n-6)+13n-4

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Solution for -11-7+3(2n-5)=-2(4n-6)+13n-4 equation: 



-11-7+3(2n-5)=-2(4n-6)+13n-4

We move all terms to the left:

-11-7+3(2n-5)-(-2(4n-6)+13n-4)=0

We add all the numbers together, and all the variables

3(2n-5)-(-2(4n-6)+13n-4)-18=0

We multiply parentheses

6n-(-2(4n-6)+13n-4)-15-18=0



We calculate terms in parentheses: -(-2(4n-6)+13n-4), so:

-2(4n-6)+13n-4

We add all the numbers together, and all the variables

13n-2(4n-6)-4

We multiply parentheses

13n-8n+12-4

We add all the numbers together, and all the variables

5n+8

Back to the equation:

-(5n+8)



We add all the numbers together, and all the variables

6n-(5n+8)-33=0

We get rid of parentheses

6n-5n-8-33=0

We add all the numbers together, and all the variables

n-41=0

We move all terms containing n to the left, all other terms to the right

n=41

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