-11+10(p+10)=4-5(2p-2)

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Solution for -11+10(p+10)=4-5(2p-2) equation: 



-11+10(p+10)=4-5(2p-2)

We move all terms to the left:

-11+10(p+10)-(4-5(2p-2))=0

We multiply parentheses

10p-(4-5(2p-2))+100-11=0



We calculate terms in parentheses: -(4-5(2p-2)), so:

4-5(2p-2)

determiningTheFunctionDomain
-5(2p-2)+4

We multiply parentheses

-10p+10+4

We add all the numbers together, and all the variables

-10p+14

Back to the equation:

-(-10p+14)



We add all the numbers together, and all the variables

10p-(-10p+14)+89=0

We get rid of parentheses

10p+10p-14+89=0

We add all the numbers together, and all the variables

20p+75=0

We move all terms containing p to the left, all other terms to the right

20p=-75

p=-75/20

p=-3+3/4

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