-11+10(n+10)=4-5(2n+11)

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Solution for -11+10(n+10)=4-5(2n+11) equation: 



-11+10(n+10)=4-5(2n+11)

We move all terms to the left:

-11+10(n+10)-(4-5(2n+11))=0

We multiply parentheses

10n-(4-5(2n+11))+100-11=0



We calculate terms in parentheses: -(4-5(2n+11)), so:

4-5(2n+11)

determiningTheFunctionDomain
-5(2n+11)+4

We multiply parentheses

-10n-55+4

We add all the numbers together, and all the variables

-10n-51

Back to the equation:

-(-10n-51)



We add all the numbers together, and all the variables

10n-(-10n-51)+89=0

We get rid of parentheses

10n+10n+51+89=0

We add all the numbers together, and all the variables

20n+140=0

We move all terms containing n to the left, all other terms to the right

20n=-140

n=-140/20

n=-7

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