-11(x+2)+5(3X-5)=3(x-4)+8

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Solution for -11(x+2)+5(3X-5)=3(x-4)+8 equation: 



-11(x+2)+5(3x-5)=3(x-4)+8

We move all terms to the left:

-11(x+2)+5(3x-5)-(3(x-4)+8)=0

We multiply parentheses

-11x+15x-(3(x-4)+8)-22-25=0



We calculate terms in parentheses: -(3(x-4)+8), so:

3(x-4)+8

We multiply parentheses

3x-12+8

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

4x-(3x-4)-47=0

We get rid of parentheses

4x-3x+4-47=0

We add all the numbers together, and all the variables

x-43=0

We move all terms containing x to the left, all other terms to the right

x=43

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