-10m(14m-13)=+19m

Solution for -10m(14m-13)=+19m equation:

-10m(14m-13)=+19m

We move all terms to the left:

-10m(14m-13)-(+19m)=0

We multiply parentheses

-140m^2+130m-(+19m)=0

We get rid of parentheses

-140m^2+130m-19m=0

We add all the numbers together, and all the variables

-140m^2+111m=0

a = -140; b = 111; c = 0;
Δ = b2-4ac
Δ = 1112-4·(-140)·0
Δ = 12321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12321}=111$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(111)-111}{2*-140}=\frac{-222}{-280}
=111/140
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(111)+111}{2*-140}=\frac{0}{-280}
=0
$