-10k+2/3(3k-6)+5=-10-(2k+7)

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Solution for -10k+2/3(3k-6)+5=-10-(2k+7) equation: 



-10k+2/3(3k-6)+5=-10-(2k+7)

We move all terms to the left:

-10k+2/3(3k-6)+5-(-10-(2k+7))=0



Domain of the equation: 3(3k-6)!=0

k∈R



We multiply all the terms by the denominator


-10k*3(3k-6)-((-10-(2k+7)))*3(3k-6)+5*3(3k-6)+2=0



We calculate terms in parentheses: -((-10-(2k+7)))*3(3k-6), so:

(-10-(2k+7)))*3(3k-6



Wy multiply elements

-30k^2(3-((-10-(2k+7)))*3(3k-6)+15k(3+2=0

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